12b^2-16bc-3c^2=

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Solution for 12b^2-16bc-3c^2= equation: 


Simplifying
12b2 + -16bc + -3c2 = 0

Reorder the terms:
-16bc + 12b2 + -3c2 = 0

Solving
-16bc + 12b2 + -3c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2b + -3c)(6b + c) = 0


Subproblem 1
Set the factor '(2b + -3c)' equal to zero and attempt to solve:

Simplifying
2b + -3c = 0

Solving
2b + -3c = 0

Move all terms containing b to the left, all other terms to the right.

Add '3c' to each side of the equation.
2b + -3c + 3c = 0 + 3c

Combine like terms: -3c + 3c = 0
2b + 0 = 0 + 3c
2b = 0 + 3c
Remove the zero:
2b = 3c

Divide each side by '2'.
b = 1.5c

Simplifying
b = 1.5c

Subproblem 2
Set the factor '(6b + c)' equal to zero and attempt to solve:

Simplifying
6b + c = 0

Solving
6b + c = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6b + c + -1c = 0 + -1c

Combine like terms: c + -1c = 0
6b + 0 = 0 + -1c
6b = 0 + -1c
Remove the zero:
6b = -1c

Divide each side by '6'.
b = -0.1666666667c

Simplifying
b = -0.1666666667c
Solution
b = {1.5c, -0.1666666667c}

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